JEE MAIN - Physics (2024 - 30th January Morning Shift - No. 1)
The ratio of the magnitude of the kinetic energy to the potential energy of an electron in the 5th excited state of a hydrogen atom is :
4
1
$$\frac{1}{2}$$
$$\frac{1}{4}$$
คำอธิบาย
$$\frac{1}{2}|P E|=K E$$ for each value of $$\mathrm{n}$$ (orbit)
$$\therefore \frac{K E}{|P E|}=\frac{1}{2}$$